Rising Factorial
Calculates the rising factorial with arguments \e x and \e n.
Controller: CodeCogs
| doublerising_factorial( | double | x | |
| int | n | ) |
The rising factorial has the following formula
Note that the number of ways of arranging n objects in m ordered boxes is
. (Here, the ordering in
each box matters). Thus, 2 objects in 2 boxes have the following 6 possible arrangements:
Moreover, the number of non-decreasing maps from a set of n to a set of m ordered elements is
.
Thus the set of nondecreasing maps from
to
is the 20 elements:
Example:
#include <codecogs/maths/discrete/combinatorics/arithmetic/rising_factorial.h> #include <iostream> int main() { std::cout << Maths::Combinatorics::Arithmetic::rising_factorial(5, 3) << std::endl; return 0; }
Output:
210References:
SUBSET, a C++ library of combinatorial routines, http://www.csit.fsu.edu/~burkardt/cpp_src/subset/subset.htmlParameters
x the first rising factorial argument n the second falling factorial argument
Returns
- the rising factorial of the pair of values x and n
Authors
- Lucian Bentea (August 2005)
Source Code
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![[x]^n = \prod_{k = 0}^{n - 1} (x + k)](/images/eqns/a6d1ba5920062d226ea371fb2296c054.gif)