engineeringstructures

deflection pp

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#include <codecogs/engineering/structures/deflection_pp.h>

using namespace Engineering::Structures;

double deflection_pp (double L, double a, double W, double x, double EI=1)
Beam deflection due to a point load with two pin jointed supports at either end.
Click for details on using CodeCogs in ExcelReal cc_structuresDeflection_pp (Real L, Real a, Real W, Real x, Real EI)
This function is available as a Microsoft Excel add-in.

Function Documentation

Deflection Pp Calculator

  

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doubledeflection_ppdoubleL
doublea
doubleW
doublex
doubleEI = 1 )
This function is used to calculate the deflection \delta(x) along a beam that is subjected to a single perpendicular point load W.

1/beam_pp.png
The deflection of the beam is calculated using the principal of virtual work, applying a unit load of 1N at the location where the deflection is required and solving
(1)
\displaystyle \delta = \frac{1}{EI} \int_0^L M(x) M_u(x) dx
where M(x) are the moment along the beam due to the applied unit load W, while M_u(x) is the moment due to the applied virtual point load at the location x.

Further information available when you purchase a licence.

Example
Calculate the deflection along a 9m long solid plank of wood (100mm x 50m) wood due to a person that weights 70kg who stands 3m from either end.

In graphical form the deflection (negative is downwards) is given by:
\graph  L=9, a=3, W=-686, x=0:9, EI=10e9

#include<stdio.h>
#include<codecogs/engineering/structures/deflection_pp.h>
 
int main()
{
  double E=10e9;      // approximate strength of wood.
  double I=1.042e-6;  // I=b*h^3/12.
  double L=9;
  double a=3;
  double W=70*9.81; // Force in Newtons
  for(int x=0;x<=L;x++)
    printf("\n deflection(x=%d)=%lf",x,
      Engineering::Structures::deflection_pp(L, a, W, x, E*I));
  return 0;
}
Output:
deflection(x=0)=0.000000
deflection(x=1)=0.322188
deflection(x=2)=0.600441
deflection(x=3)=0.790825
deflection(x=4)=0.860389
deflection(x=5)=0.820115
deflection(x=6)=0.691972
deflection(x=7)=0.497927
deflection(x=8)=0.259947
deflection(x=9)=0.000000
Parameters:
LThe length of the beam. [m]
aThe location of the point load applied to the beam. [m]
WThe point load applied at location a in a direction perpendicular to the main beam. [N]
xThe point at which the deflection should be calculated
EIThe Modulus of Elasticity (E) multiplied with the Second Moment of Area (I) for the specified beam. See Young's Modulus for example values. [N/m^2]
Source Code:
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Last Modified: 6 Nov 07 @ 09:50     Page Rendered: 2008-05-13 20:21:10

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