financeaccounting

depreciation

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Interface

#include <codecogs/finance/accounting/depreciation.h>

using namespace Finance::Accounting;

double depreciation (double valCost,              double valSalv,              int life,              int per,              double fact=2.0)
Return the depreciation for a specified period using the fixed-declining balance method. Excel: DDB
Click for details on using CodeCogs in ExcelReal cc_depreciation (Real valCost, Real valSalv, Integer life, Integer per, Real fact)
This function is available as a Microsoft Excel add-in.

Function Documentation

Depreciation Calculator

  

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doubledepreciationdoublevalCost
doublevalSalv
intlife
intper
doublefact = 2.0 )
This function calculates the depreciation of an asset for a specified period. The method used is a fixed-declining method. This function is equivalent to the Microsoft Excel function DDB. It works on the following set of equations:
(1)
\displaystyle rate = 1.0 - (\frac{salv}{cost})^{(\frac{1}{life})}

(2)
\displaystyle deprec = (cost-prevTot)*rate

With two special cases, when period=1:
(3)
\displaystyle deprec = cost*rate*\frac{month}{12}

When period=life:
(4)
\displaystyle deprec = (cost-prevTot)*rate*\frac{12-month}{12}

Where:
Example:
#include <stdio.h>
#include <codecogs/finance/accounting/deprecfixeddec.h>
 
int main(void)
{
  double costVal=1000000;
  double salvVal=100000;
  
  printf("Consider an asset with the following terms:\n");
  printf("Cost\t\tSalvage\t\tLife\tPeriod\tMonth\tDepreciation\n");
 
  for (int per=1; per<=7; ++per) 
  { 
    printf("%f\t%f\t6\t%i\t7\t%f\n",
           costVal,
           salvVal,
           per,
           Finance::Accounting::deprecFixedDec(costVal, salvVal, 6, per, 7));
  }
   
  printf("\n");
  costVal=2500;
  salvVal=500;
  for (int per=1; per<=4; ++per) 
  { 
    printf("%f\t%f\t3\t%i\t6\t%f\n",
           costVal,
           salvVal,
           per,
           Finance::Accounting::deprecFixedDec(costVal, salvVal, 3, per, 6));
  }
  
  return 0;
}
Output:
Consider an asset with the following terms:
Cost            Salvage         Life    Period  Month   Depreciation
1000000.000000  100000.000000   6       1       7       186083.333333
1000000.000000  100000.000000   6       2       7       259639.416667
1000000.000000  100000.000000   6       3       7       176814.442750
1000000.000000  100000.000000   6       4       7       120410.635513
1000000.000000  100000.000000   6       5       7       81999.642784
1000000.000000  100000.000000   6       6       7       55841.756736
1000000.000000  100000.000000   6       7       7       15845.098474
 
2500.000000     500.000000      3       1       6       518.750000
2500.000000     500.000000      3       2       6       822.218750
2500.000000     500.000000      3       3       6       480.997969
2500.000000     500.000000      3       4       6       140.691906
Parameters:
valCostThe initial cost of the asset.
valSalvThe salvage value of the asset at the end of its life.
lifeThe is the number of periods over which the asset is being depreciated (sometimes called the useful life of the asset).
perThe period for which you want to calculate the depreciation. per must have the same units as life.
factDefault Value = 2.0
Returns:
The depreciation for each accounting period.
References:
http://www.vni.com/products/imsl/jmsl/v30/api/
Authors:
James Warren (August 2005)
Source Code:
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Last Modified: 18 Oct 07 @ 17:07     Page Rendered: 2008-05-08 21:18:11

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