Maths › Data Fitting ›
Least Squares
Curve fitting, least squares, optimization
Introduction
Consider a series of- When
the method is known as univariate regression, while if
we have multivariate regression.
- Provided that all the functions
are linear, the method is called linear regression, otherwise it is known as nonlinear regression.
- Also, based on the type of the functions
we may have polynomial regression, regression by orthogonal polynomials, and so on.
Solving The Problem
Since the sum of residuals functionReferences
- http://en.wikipedia.org/wiki/Curve_fitting
- http://en.wikipedia.org/wiki/Regression_analysis
- http://en.wikipedia.org/wiki/Least_squares
- Franklin A. Graybill, Hariharan K. Iyer, Regression Analysis. Concepts and Applications, Duxbury Press, Belmont, California.
Login

![S_f(\alpha_1, \alpha_2, \ldots, \alpha_k) := \sum_{i = 1}^N \left[y_i - f(\alpha_1, \alpha_2, \ldots, \alpha_k; x_i)\right]^2.](/images/eqns/cdb4a7926a8b75bf9cb9b73e81c41d74.gif)
![\begin{array}{rcl} \displaystyle \frac{\partial S_f}{\partial \alpha_j} &=& \displaystyle \sum_{i = 1}^N \frac{\partial}{\partial \alpha_j} \left[y_i - f(\alpha_1, \alpha_2, \ldots, \alpha_k; x_i)\right]^2 \\ \\ &=& \displaystyle 2 \sum_{i = 1}^N \left[y_i - f(\alpha_1, \alpha_2, \ldots, \alpha_k; x_i)\right] \frac{\partial}{\partial \alpha_j} \left[y_i - f(\alpha_1, \alpha_2, \ldots, \alpha_k; x_i)\right] \\ \\ &=& \displaystyle 2 \sum_{i = 1}^N \left[y_i - \sum_{r = 1}^k \psi_r(\alpha_r) \phi_r(x_i) \right] \frac{\partial}{\partial \alpha_j} \left[y_i - \sum_{r = 1}^k \psi_r(\alpha_r) \phi_r(x_i) \right] \\ \\ &=& \displaystyle - 2 \psi'_j(\alpha_j) \sum_{i = 1}^N \phi_j(x_i) \left[y_i - \sum_{r = 1}^k \psi_r(\alpha_r) \phi_r(x_i) \right]. \end{array}](/images/eqns/0e3150bd7e7790d1082326f00599dcbe.gif)
![\left\{ \begin{array}{ccc} \displaystyle \psi'_1(\alpha_1^*) \sum_{i = 1}^N \phi_1(x_i) \left[y_i - \sum_{r = 1}^k \psi_r(\alpha_r^*) \phi_r(x_i) \right] &=& 0 \\ \\ \displaystyle \psi'_2(\alpha_2^*) \sum_{i = 1}^N \phi_2(x_i) \left[y_i - \sum_{r = 1}^k \psi_r(\alpha_r^*) \phi_r(x_i) \right] &=& 0 \\ \\ \cdots\qquad\cdots\qquad\cdots\\ \displaystyle \psi'_k(\alpha_k^*) \sum_{i = 1}^N \phi_k(x_i) \left[y_i - \sum_{r = 1}^k \psi_r(\alpha_r^*) \phi_r(x_i) \right] &=& 0. \\ \\ \end{array} \right.](/images/eqns/930df998e95dfe999fec84cafb2cb705.gif)