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Maths

Simple Algebraic Differentiation

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Differentiation From First Principles

In exams it is sometimes required that Differentiation be carried out from first principles.

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The Differential Coefficient (gradient Function)

\displaystyle \mathbf{\frac{dy}{dx}} is known as the Gradient

Function
and represents the Derivative of y with respect of x. It is also known as the Differential Coefficient.

In the simplest case:-

Example 1:
Example 2:

It is not possible to differentiate the above equation term by term. It must either be multiplied out or treated as a product of two variables. ( See "Product Rule") The choice of which to use depends on which is the best solution for a particular equation.

Then this must be multiplied out to give:-

And So:-

Example 3:
Find the gradient of the curve (y=6x^4+2x^3-5x+6) at x=1

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Example 4:
If the distance traveled by a particle in time t is given by:-

Where u and a are constants show that the velocity at time t is u +at

Note. Velocity is the rate at which a particle moves in a straight line from a fixed point and is thus \displaystyle \frac{ds}{dt}

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Example 5:
Differentiate with respect to x

And find the slope of the Tangent at x=2 \;\;\;and\;\;\;x=1.4

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The Differentiation 0f A Product Of Two Functions Of X

It is obvious, that by taking two simple factors such as 5 X 8 that the total increase in the product is Not obtained by multiplying together the increases of the separate factors and therefore the Differential Coefficient is not equal to the product of the d.c's of its factors.

Proof Of The Above Equation:
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Example 6:
Example 7:
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Example 8:
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Example 9:

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Example 10:
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The Differentiation Of A Product Of Any Number Of Functions Of X

The rule for finding the differential coefficient of a product of two functions of x can be extended to apply to the product of any finite numbers of functions of x

Where u, v, w are all functions of x, then regarding this as the product of the two factors un and w:-

And similarly for any finite number of factors.

Note An important result follows from the above rules. The differential coefficient of y^2 with respect to x can be considered to be the product of two factors each of x and hence is given by:-

Similarly, if n is any interger, by taking the product of n factors each of y

The Differentiation Of A Quotient Of Two Functions Of X

The following is the proof from first principles of the above equation.

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Example 11:
Example 12:
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Example 13:
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Last Modified: 2010-07-20 17:49:32     Page Rendered: 2010-07-31 18:30:08