dayOfYear

This function calculates the day of the year from a serial date, such that 1st January = 1 and 31st December = 365 or 366 in a leap year. The Gregorian calendar is assumed for these calculations. The most general solution for our Julian mode is:

(1)

(2)

(3)

where nDate is equal to the Julian Period, and all division are integer divisions.

#include <stdio.h>
#include <codecogs/units/date/dayofyear.h>
#include <codecogs/units/date/date.h>
using namespace Units::Date;

int main()
{
  for(int i=5;i<15;i++)
  {
    int adate=date(2004, 2, i);
    printf("\n %d February 2004 is %d day of year", i, dayOfYear(adate));
  }
  return 0;
}

Parameters