# Lagrange

Interpolates a given set of points using the Lagrange polynomial.

Controller: **CodeCogs**

## Interface

C++

## Class Lagrange

The Lagrange interpolating polynomial is the polynomial of degree n - 1 that passes through the n points It is given by where The formula was first published by Waring (1779), rediscovered by Euler in 1783, and published by Lagrange in 1795 (Jeffreys and Jeffreys 1988). An important detail when using this class is that the abscissas array given as argument to the constructor needs to be sorted in ascending order. Below you will find the interpolation graphs for a set of points obtained by evaluating the function , displayed in light blue, at particular abscissas. The Lagrange polynomial, displayed in red, has been calculated using this class. In the first graph there had been chosen a number of 12 points, while in the second 36 points were considered. The level of interpolation in both graphs is 3. The root mean squared error is also displayd in each of the cases.## References:

- MathWorld, http://mathworld.wolfram.com/LagrangeInterpolatingPolynomial.html
- Jean-Pierre Moreau's Home Page, http://perso.wanadoo.fr/jean-pierre.moreau/
- F.R. Ruckdeschel, "BASIC Scientific Subroutines, Vol. II, BYTE/McGRAWW-HILL, 1981

### Example 1

- The following example displays 20 interpolated values (you may change this amount through
the N_out variable) for the given function with abscissas equally spaced in the
interval. The X and Y coordinate arrays are initialized by evaluating
this function for N = 12 points equally spaced in the domain from to .
#include <codecogs/maths/interpolation/lagrange.h> #include <cmath> #include <iostream> #include <iomanip> using namespace std; #define PI 3.1415 #define N 12 int main() { // Declare and initialize two arrays to hold the coordinates of the initial data points double x[N], y[N]; // Generate the points double xx = PI, step = 4 * PI / (N - 1); for (int i = 0; i < N; ++i, xx += step) { x[i] = xx; y[i] = sin(2 * xx) / xx; } // Initialize the Lagrange interpolation routine with known data points Maths::Interpolation::Lagrange A(N, x, y); // Interrogate Lagrange polynomial to find interpolated values int N_out = 20; xx = PI, step = (3 * PI) / (N_out - 1); for (int i = 0; i < N_out; ++i, xx += step) { cout << "x = " << setw(7) << xx << " y = "; cout << setw(13) << A.getValue(xx, 3) << endl; } return 0; }

Output:x = 3.1415 y = -5.89868e-005 x = 3.63753 y = 0.216649 x = 4.13355 y = 0.208793 x = 4.62958 y = -0.0536974 x = 5.12561 y = -0.186543 x = 5.62163 y = -0.10577 x = 6.11766 y = 0.0268879 x = 6.61368 y = 0.0875189 x = 7.10971 y = 0.0993752 x = 7.60574 y = 0.0512131 x = 8.10176 y = -0.0885626 x = 8.59779 y = -0.123293 x = 9.09382 y = -0.0160297 x = 9.58984 y = 0.0787203 x = 10.0859 y = 0.0791771 x = 10.5819 y = 0.0216086 x = 11.0779 y = -0.0212055 x = 11.5739 y = -0.0727429 x = 12.07 y = -0.0621462 x = 12.566 y = 0.0312161

## See Also

Also consider the regression methods: Regression/Discrete, Regression/Forsythe, Regression/Orthogonal, Regression/Stiefel### Authors

*Lucian Bentea (August 2005)*

##### Source Code

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## Members of Lagrange

#### Lagrange

Initializes the necessary data for following evaluations of the polynomial.Lagrange( int `n`double* `x`double* `y`) *[constructor]*n The number of initial points x The x-coordinates for the initial points y The y-coordinates for the initial points

#### GetValue

Returns the approximated ordinate at the given abscissa.doublegetValue( double `x`int `l`) ### Note

- The value of the x parameter needs to be in the X[0]...X[N - L + 1] interval (including endpoints), where l > 1 is the level of interpolation. For example a level 3 interpolation would have the maximum working interval between X[0] and X[N - 2].

x The abscissa of the interpolation point l The level of interpolation (2 means quadratic)

## Lagrange Once

doubleLagrange_once( | int | N | |

double* | x | ||

double* | y | ||

double | a | ||

int | l | ) |

### Example 2

- The following graph is constructed from interpolating the following values:
x = 1 y = 0.22 x = 2 y = 0.04 x = 3 y = -0.13 x = 4 y = -0.17 x = 5 y = -0.04 x = 6 y = 0.09 x = 7 y = 0.11

Graph is not currently available

### Parameters

N The number of initial points x The x-coordinates for the initial points (evenly spaced!) y The y-coordinates for the initial points a The x-coordinate for the output point l The level of interpolation (2 means quadratic)

### Returns

- the interpolated y-coordinate that corresponds to
*a*.

##### Source Code

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