A discussion on the expansion and compression of ideal gases, also considering the particular cases of isothermal and adiabatic processes

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The expansion and compression of ideal gases are regularly considered to be polytropic processes. Therefore, they satisfy the equation:

$$PV^n = const.$$
(13)

where $n$ is called the polytropic index.

However, we also know that ideal gases follow the so-called combined gas law (for a more detailed discussion also see Thermodynamics of Ideal Gases ), which states that:

$$\frac{PV}{T} = const.$$
(14)

Therefore, when dividing equation (13) by $\displaystyle \frac{PV}{T}$ we will also get a constant:

$$PV^n \div \frac{PV}{T} = const.$$
(15)

or, written in a different form:

$$PV^n \cdot \frac{T}{PV} = const.$$
(16)

from which we obtain that, during an expansion or compression, ideal gases satisfy:

$$TV^{n-1} = const.$$
(17)

Also, we can rewrite equation (14) as:

$$V = const. \cdot \frac{T}{P}$$
(18)

By using the expression form of the volume from (18) in equation (13), we get that:

$$\frac{PT^n}{P^n} = const.$$
(19)

which leads to another equation which is satisfied during the expansion or compression of ideal gases:

$$\frac{T}{P^\frac{n-1}{n}} = const.$$
(20)

Let us now consider the work done during a polytropic expansion or compression. We know that the work done by a gas which is expanding from state $1$ to state $2$ is given by:

$$W = \int_1^2 PdV$$
(21)

As this is a polytropic expansion, we also have that:

$$PV^n = C$$
(22)

or furthermore, that:

$$P = \frac{C}{V^n}$$
(23)

where $C$ is a constant and $n$ the polytropic index. By using the expression of pressure from (23) in equation (21), we get the work done by the gas as:

$$W = C \int_1^2 V^{-n} dV$$
(24)

which, integrated, leads to:

$$W = C \left( \frac{V^{-n+1}}{-n+1} \right) \bigg|_1^2$$
(25)

By using identity (22) again, we can rewrite (25) as:

$$W = \left( PV^n \frac{V^{1-n}}{1-n} \right) \bigg|_1^2$$
(26)

or furthermore, as:

$$W = \left( \frac{PV}{1-n} \right) \bigg|_1^2$$
(27)

Thus, we obtain the work done by the gas during a polytropic expansion as:

$$W = \frac{P_2 V_2 - P_1 V_1}{1-n}$$
(28)

However, from the ideal gas law we also have that:

$$PV = m \tilde{R} T$$
(29)

where $m$ is the number of moles, and $\tilde{R}$ the universal gas constant (for additional information also see Thermodynamics of Ideal Gases ). Therefore, we have that:

$$P_1 V_1 = m \tilde{R} T_1$$
(30)

and:

$$P_2 V_2 = m \tilde{R} T_2$$
(31)

By using (30) and (31), the work done from equation (28) becomes:

$$W = \frac{m \tilde{R} T_2 - m \tilde{R} T_1}{1-n}$$
(32)

from which we obtain the work done by the gas during a polytropic expansion also as:

$$W = \frac{m \tilde{R} (T_2 - T_1)}{1-n}$$
(33)

In order to calculate the work done on a gas undergoing a polytropic compression from state $1$ to state $2$, we follow a similar reasoning, but this time starting from:

$$W = - \int_1^2 PdV$$
(34)

Therefore, equations (28) and (33) can be rewritten in order to express the work done during a polytropic compression as:

$$W = - \frac{(P_2 V_2 - P_1 V_1)}{1-n}$$
(35)

and:

$$W = - \frac{m \tilde{R} (T_2 - T_1)}{1-n}$$
(36)

respectively. Hence, we obtain that the work done during a polytropic compression can be expressed as:

$$W = \frac{P_1 V_1 - P_2 V_2}{1-n}$$
(37)

or as:

$$W = \frac{m \tilde{R} (T_1 - T_2)}{1-n}$$
(38)

Let us now consider the heat supplied during a polytropic expansion. From the first law of thermodynamics we know that the heat added to the system $Q$ equals the change in internal energy $\Delta U$ plus the work done by the system $W$:

$$Q = \Delta U + W$$
(39)

As the change in internal energy is given by:

$$\Delta U = m C_V (T_2 - T_1)$$
(40)

where $m$ is the number of moles, and $C_V$ the molar heat capacity at constant volume (for a more detailed discussion also see Thermodynamics of Ideal Gases ). Also taking into account the expression of the work done during a polytropic expansion from (32), the heat supplied during a polytropic expansion becomes:

$$Q = m C_V (T_2 - T_1) + \frac{m \tilde{R} (T_2 - T_1)}{1-n}$$
(41)

which can also be written as:

$$Q = (T_2 - T_1) \left( m C_V + \frac{m \tilde{R}}{1-n} \right)$$
(42)

We know that the universal gas constant $\tilde{R}$ relates the heat capacity at constant volume $C_V$ to the heat capacity at constant pressure $C_P$ by:

$$C_P - C_V = \tilde{R}$$
(43)

(for a more detailed discussion also see Thermodynamics of Ideal Gases ). However, from the definition of the heat capacity ratio $\gamma$:

$$\gamma = \frac{C_P}{C_V}$$
(44)

we also have that:

$$C_P = \gamma C_V$$
(45)

By using the expression of $C_P$ from (45) in equation (43), we get that:

$$\gamma C_V - C_V = \tilde{R}$$
(46)

or furthermore, that:

$$C_V (\gamma - 1) = \tilde{R}$$
(47)

from which we obtain $C_V$ as:

$$C_V = \frac{\tilde{R}}{\gamma - 1}$$
(48)

By using the expression of $C_V$ from (48) in equation (42), we get the heat supplied during a polytropic expansion as:

$$Q = (T_2 - T_1) \left( \frac{m \tilde{R}}{\gamma - 1} + \frac{m \tilde{R}}{1-n} \right)$$
(49)

or furthermore, as:

$$Q = m \tilde{R} (T_2 - T_1) \left( \frac{1}{\gamma - 1} + \frac{1}{1-n} \right)$$
(50)

Equation (50) leads to:

$$Q = m \tilde{R} (T_2 - T_1) \left[ \frac{1-n+\gamma - 1}{(\gamma -1)(1-n)} \right]$$
(51)

or, furthermore, to:

$$Q = m \tilde{R} (T_2 - T_1) \frac{(\gamma - n)}{(\gamma - 1)(1-n)}$$
(52)

Taking into account that $\displaystyle \frac{m \tilde{R} (T_2 - T_1)}{1-n} = W$ (see equation 33), we obtain the heat supplied during a polytropic expansion as:

$$Q = W \frac{(\gamma - n)}{\gamma - 1}$$
(53)

where $\gamma$ is the heat capacity ratio, $n$ the polytropic index, and $W$ the work done during the expansion.

Isothermal Expansion or Compression

For different values of the polytropic index $n$, the polytropic process defined by (13) will be equivalent to other particular processes. For instance, if $n=1$, equation (13) will be rewritten as:

$$PV = const.$$
(54)

However, taking into account the ideal gas law (see 29), this also means that:

$$m \tilde{R} T = const.$$
(55)

As $m$ and $\tilde{R}$ are constants, this leads to:

$$T = const.$$
(56)

which means that for $n=1$, we are dealing with isothermal processes.

The work done during a process which changes the system from state $1$ to state $2$ is given by $W=\int_1^2 PdV$. In addition, taking into account that $\displaystyle P=\frac{m \tilde{R} T}{V}$ (see the ideal gas law from equation 29), we get the work done during an isothermal expansion or compression as:

$$W = \int_1^2 \frac{m \tilde{R} T}{V} dV$$
(57)

from which we obtain:

$$W = m \tilde{R} T ln \frac{V_2}{V_1}$$
(58)

Let us now consider the heat exchanged during an isothermal expansion or compression. The change in internal energy in this case is $\Delta U = 0$, as $T_1=T_2$ (see equation 40). Therefore, from the first law of thermodynamics (see 39), we obtain that for an isothermal process, the heat exchanged equals the work done:

$$Q = W$$
(59)

Adiabatic Expansion or Compression

Another particular case of the polytropic processes is when the polytropic index equals the heat capacity ratio, i.e. when $n=\gamma$. In this case, the heat exchanged during the process (see equation 53) will be:

$$Q = 0$$
(60)

Therefore, when $n=\gamma$, we are dealing with adiabatic processes. This can also be demonstrated the other way around. Consider for example, that we are dealing with an adiabatic process. As $\delta Q = 0$ and $\delta W = PdV$, we obtain from the first law of thermodynamics (see 39) written for infinitesimal changes, that:

$$PdV = -dU$$
(61)

We can write the infinitesimal change in internal energy as (see equation 40):

$$dU = m C_V dT$$
(62)

where $m$ is the number of moles, $C_V$ the molar heat capacity at constant volume, and $dT$ the infinitesimal change in temperature. Therefore, equation (61) becomes:

$$PdV = - m C_V dT$$
(63)

However, $\displaystyle P=\frac{m \tilde{R} T}{V}$ (see the ideal gas law from equation 29). Hence, we can also write equation (63) as:

$$\frac{m \tilde{R} T}{V} dV = -m C_V dT$$
(64)

or furthermore, as:

$$\tilde{R} \frac{dV}{V} = - C_V \frac{dT}{T}$$
(65)

By integrating equation (65) we get that:

$$\tilde{R} ln V + C_V ln T = const.$$
(66)

which can also be written as:

$$ln V^{\tilde{R}} + ln T^{C_V} = const.$$
(67)

or furthermore, as:

$$ln (V^{\tilde{R}} \cdot T^{C_V}) = const.$$
(68)

By raising $e$ to equation (68), we get that:

$$V^{\tilde{R}} \cdot T^{C_V} = const.$$
(69)

Then, by raising equation (69) to the $\displaystyle \frac{1}{C_V}$ power, we get that:

$$V^\frac{\tilde{R}}{C_V} \cdot T = const.$$
(70)

From equation (47) we can also write that:

$$\frac{\tilde{R}}{C_V} = \gamma - 1$$
(71)

Therefore, equation (70) becomes:

$$V^{\gamma - 1} \cdot T = const.$$
(72)

However, we know that all polytropic processes satisfy $V^{n-1} \cdot T = const.$ (see equation 17). By coupling this with equation (72) we obtain that, indeed for adiabatic processes, $n=\gamma$.

Let us now consider the work done during an adiabatic expansion or compression. As $n=\gamma$, the work done during an adiabatic expansion is given by (see equation 33):

$$W = \frac{m \tilde{R} (T_2 - T_1)}{1-\gamma}$$
(73)

However, as $\displaystyle \frac{\tilde{R}}{1-\gamma} = - C_V$ (see 48), equation (73) becomes:

$$W = -m C_V (T_2 - T_1)$$
(74)

Taking into account equation (62), we obtain the work done during an adiabatic expansion as:

$$W = -\Delta U$$
(75)

where $\Delta U$ is the change in internal energy.

By following a similar reasoning, we obtain the work done during an adiabatic compression (given by equation 38 when $n=\gamma$) as:

$$W = \Delta U$$
(76)

where $\Delta U$ is the change in internal energy.