Inductance of a circuit, mutual inductance, and the energy stored in terms of inductance

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In order to define the inductance, consider a coil of wire as the one diagramed in Figure 1.

Figure 1
Figure 1

The induced voltage e at any instant is:

e = N \frac{d\Phi}{dt}
(9)

where N is the number of wire turns, and \Phi the magnetic flux. As we can also write that:

\frac{d\Phi}{dt} = \frac{d\Phi}{di} \frac{di}{dt}
(10)

equation (#1) becomes:

e = N \frac{d\Phi}{di} \frac{di}{dt}
(11)

The term N \frac{d\Phi}{di} is denoted by L and is called (self-) inductance. Thus, the inductance is:

L = N \frac{d\Phi}{di}
(12)

and equation (#3) becomes:

e = L \frac{di}{dt}
(13)

Inductance can be illustrated by the behavior of a coil of wire which resists any change of electric current that passes through it. The unit of inductance is the Henry (H). Thus, a coil has an inductance of 1\;H if an induced voltage of 1\;V flows through it with a rate of change of current of 1\; A/s.

Calculation of Self Inductance

In order to calculate the self inductance, consider a circuit of length l and cross-sectional area A, which is passed by a coil of N turns (see Figure 2).

Figure 2
Figure 2

Also, assume that the area of the core is small, and that the magnetic field strength H is constant across the area. We can then write that:

H l = N I
(14)

or, furthermore, that:

H = \frac{N I}{l}
(15)

where I is the current which passes through the coil (for a more detailed discussion on the magnetic field strength see Field Strength ). We also know that the magnetic field strength H is related to the magnetic flux density B by the equation:

B = \mu_0 \mu_r H
(16)

where \mu_0 is the magnetic permeability of free space, and \mu_r the relative magnetic permeability. Taking into account (#7), equation (#8) becomes:

B = \frac{\mu_0 \mu_r N I}{l}
(17)

As the magnetic flux density B is defined as:

B = \frac{\Phi}{A}
(18)

where \Phi is the magnetic flux, equation (#9) becomes:

\frac{\Phi}{A} = \frac{\mu_0 \mu_r N I}{l}
(19)

from which we obtain the magnetic flux as:

\Phi = A \frac{\mu_0 \mu_r N I}{l}
(20)

From the definition of the inductance L (see equation #4), we can also write that:

\calc{A*((4*π*10^(-7)*mu_r*N^2)/l)} "Instant calculator eq(14)"

L = \frac{N \Phi}{I}
(21)

Using (#12) in (#13) gives the following expression of the self inductance:

L = A \frac{\mu_0 \mu_r N^2}{l}
(22)

Mutual Inductance

Mutual inductance represents the generation of an electromotive force (emf) in a coil as a result of a change in current in a coupled coil as the one diagramed in Figure 3.

Figure 3
Figure 3

The emf induced in coil 2 due to changes in coil 1 can be expressed as:

emf_2 = N_2 \frac{d\Phi_{1.2}}{dt}
(23)

or, furthermore, as:

emf_2 = N_2 \frac{d\Phi_{1.2}}{di_1} \frac{di_1}{dt}
(24)

We defined the mutual inductance between coil 1 and coil 2, M, as:

M = N_2 \frac{d\Phi_{1.2}}{di_1}
(25)

In this definition, M represents the ratio between the emf generated in coil 2 and the change in current in coil 1 responsible for generating this emf.

In the case of no magnetic saturation, the mutual inductance can be written as:

M = N_2 \frac{\Phi_{1.2}}{I_1}
(26)

Using (#17), equation (#16) becomes:

emf_2 = M \frac{di_1}{dt}
(27)

The best known application of mutual inductance is the transformer.

The Reciprocal Property of Inductance

Consider the coupled coil circuit diagramed in Figure 4.

Figure 4
Figure 4

From our previous discussion on mutual inductance, and also considering that there is no magnetic saturation, we can write that:

M = N_2 \frac{\Phi_{1.2}}{I_1}
(28)

and also that:

M = N_1 \frac{\Phi_{2.1}}{I_2}
(29)

Taking into account (#20) and (#21), we can write that:

\frac{\Phi_{1.2}}{\Phi_{2.1}} = \frac{N_1 I_1}{N_2 I_2}
(30)

As the two coils are wound on the same core, we have that \Phi_{1.2} = N_1 and \Phi_{2.1}=N_2. However, for more complicated cases, such relations are harder to see.

The Induced Voltage of Two Coils in Series using Inductance

Consider two coils arranged in series, as diagramed in Figure 5.

Figure 5
Figure 5

There are four induced electromotive forces due to self and mutual inductance. As such, the induced voltage at any instant can be written as:

e = L_1 \frac{di}{dt} + L_2 \frac{di}{dt} + M \frac{di}{dt} + M \frac{di}{dt}
(31)

or, furthermore, as:

e = (L_1 + L_2 + 2M) \frac{di}{dt}
(32)

where L_1 is the inductance of the first coil, L_2 the inductance of the second coil, and M the mutual inductance.

Equation (#24) applies only when the turns are additive. If the turns are opposite, equation (#24) becomes:

e = (L_1 + L_2 - 2M) \frac{di}{dt}
(33)

where the term (L_1 + L_2 - 2M) is called equivalent inductance.

Energy Stored in Terms of Inductance

The energy stored in a magnetic field can also be expressed using the (self-) inductance (for a more detailed discussion on the energy stored in a magnetic field see Stored Energy ). For example, equation (#5) can also be written as:

e\cdot i = L\cdot i \cdot \frac{di}{dt}
(34)

or, furthermore, as:

e\cdot i\cdot dt = L\cdot i\cdot di
(35)

As the energy released from the coil in a time dt is:

E = e\cdot i \cdot dt
(36)

\calc{(L*I^2)/2} "Instant calculator eq(29)"

and also taking into account (#27), we can write the energy stored in terms of inductance as:

E_{stored} = \int Lidi = \frac{1}{2} L I^2
(37)

where I is the current through the inductor.

Reference