CodeCogs

Discharge over a Triangular Notch

You're viewing an older version of this page (#4206). View the current version.

A triangular notch is also called a V-notch. Consider a triangular notch, in one side of the tank, over which water is flowing as shown in figure.

Let,

H = Height of the liquid above the apex of the notch
θ = Angle of the notch
C\_d = Coefficient of discharge

From the geometry of the figure, we find that the width of the notch at the water surface, $= 2H\tan \frac{\theta}{2}$

$\therefore$ Area of the strip = $2(H-h)\tan \frac{\theta}{2}. dh$

We know that the theoretical velocity of water through the strip = $\sqrt {2gh}$

and discharge over the notch, $dq = C_d \times Area\;of\;strip \times Theoretical\;velocity$ $\Rightarrow dq = C_d \times 2(H-h)\tan \frac{\theta}{2}. dh\sqrt {2gh}$

The total discharge over the whole notch may be found out only by integrating the above equation within the limits 0 and H.

$Q = \int_{0}^{H} C_d \times 2(H-h)\tan \frac{\theta}{2}. dh\sqrt {2gh}$

$\Rightarrow Q = 2C_d\sqrt {2g}\times \tan \frac{\theta}{2} \int_{0}^{H} (H-h)\sqrt h dh$

$\Rightarrow Q = 2C_d\sqrt {2g}\times \tan \frac{\theta}{2}\int_{0}^{H} (Hh^\frac{1}{2}-h^\frac{3}{2}) dh$

$\therefore Q = \frac{8}{15}C_d \sqrt {2g} \tan \frac{\theta}{2}\times H^{\frac{5}{2}}$

A triangular notch gives more accurate results for low discharges than rectangular notch and the same triangular notch can measure a wide range of flows accurately.

Example 1 [metric]

Problem

A right-angled V-notch was used to measure the discharge of a centrifugal pump. If the depth of water at V-notch is 200mm, calculate the discharge over the notch in liters per minute. Assume coefficient of discharge as 0.62.

Workings

Given,