An analysis of Axial Flow Turbines using both the Euler and Aerofoil Theories.

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Introduction

Almost all electrical power on Earth is produced with a turbine of some type. Very high efficiency steam turbines harness about 40% of the thermal energy, with the rest exhausted as waste heat.

Most jet engines rely on turbines to supply mechanical work from their working fluid and fuel, as do all nuclear ships and power plants.

In an axial flow turbine, the working fluid flows along the axis of the rotating turbine wheels. In this section we use the Euler and Aerofoil theories to analyze the efficiency and power output of axial flow turbines.

Axial turbine

An axial turbine operates in the reverse of an axial compressor. A set of static guide vanes or nozzle vanes accelerates and adds swirl to the fluid and directs it to the next row of turbine blades mounted on a turbine rotor.

23287/Axial-Flow-Turbines-001.png

As with a Pump consider an element at radius r.

23287/Axial-Flow-Turbines-002.png

v = v_1 = \frac{2\pi RN}{60}

Q = \pi \left(R_0^2 - R_{Boss}^2 \right)V_f

V_1 = V_{f1} = V_f

The Euler Theory

Work done by the water on the Vanes per lb. = \displaystyle\frac{V_w\,v}{g} ( It is assumed that there is no whirl at exit).

Applying Bernoulli'\b{s equation} across the Vanes and assuming no losses:

\frac{p}{w} + \frac{V^2}{2g} = \frac{p_1}{w} + \frac{V_1^2}{2g} + \frac{V_w\,v}{g}

\frac{p - p_1}{w} = \frac{V_w\,v}{g} + \frac{V_1^2 - V^2}{2g}

But since: V^2 = V_w^2 + V_f^2 = V_w^2 + V_1^2

\frac{p - p_1}{w} = \frac{V_w\,v}{g} - \frac{V_w^2}{2g}

Hydraulic \eta  =  \displaystyle\frac{V_w,v}{gH}

The Aerofoil Theory used for Turbines

Combining the Velocity Triangles:

23287/Axial-Flow-Turbines-003.png

The following diagram is a sketch through one of the Vanes:

23287/Axial-Flow-Turbines-004.png

Consider the Vanes as Aerofoils in a fluid stream of Velocity V_{r\,ave.} in a direction \theta_{ave}.

For an elemental thickness dR at a radius R.


Lift L L = C_L\times \frac{1}{2}\;\rho\; V_{r\,ave.}^2\times C\times dR\;\;\;lbs.

Drag D D = C_D\times \frac{1}{2}\;\rho\; V_{r\,ave.}^2\times C\times dR\;\;\;lbs.

(where C= Chord)
The vector sum of L and D is the resultant force P on the Vane element.


The components of P in the tangential Direction is given by:

P_t = L\;Sin\,\theta _{ave} - D\;Cos\,\theta _{ave.}\;\;\;lbs.

And the Axial component is :

P_a = L\;Cos\,\theta _{ave} + D\;Sin\,\theta _{ave.}\;\;\;lbs.

For n Vanes:



The Total Tangential Force = n Pt



The Torque T = n Pt X R



The Horse Power output = \frac{2\pi NT}{550\times 60}

Total Axial Force = n Pa = The Thrust on the Bearings.