strcoll_l
Compare strings according to current collation
Interface
#include <string.h>| int | strcoll (const char *s1, const char *s2) |
#include <xlocale.h>
| int | strcoll_l (const char *s1, const char *s2, locale_t loc) |
Description
The strcoll function lexicographically compares the null-terminated stringss1 and s2 according to the current locale collation if any, otherwise call strcmp, and returns an integer greater than, equal to, or less than 0, according as s1 is greater than, equal to, or less than s2.
While the strcoll function uses the current locale, the strcoll_l function may be passed a locale directly. See xlocale for more information.
Example:
Example - Compare strings according to current collation
Workings
#include <stdio.h> #include <string.h> int main() { // define two strings s, t and initialize s char s[10] = "testing", t[10]; // copy s to t strcpy(t, s); // test if s is identical to t if (!strcoll(s, t)) printf("The strings are identical."); else printf("The strings are different."); return 0; }
Solution
Output:
The strings are identical.
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