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# make_heap

Converts a range into a heap

## Definition

The make_heap() algorithm is defined in the standard header <algorithm> and in the nonstandard backward-compatibility header <algo.h>.

## Interface

```#include <algorithm>
template < class RandomAccessIterator >
void make_heap(
RandomAccessIterator first,
RandomAccessIterator last
);
template < class RandomAccessIterator, class BinaryPredicate >
void make_heap(
RandomAccessIterator first,
RandomAccessIterator last,
BinaryPredicate comp
);```

Parameters:
Parameter Description
first A random-access iterator addressing the position of the first element in the range to be converted into a heap
last A random-access iterator addressing the position one past the final element in the range to be converted into a heap
comp User-defined predicate function object that defines sense in which one element is less than another. A binary predicate takes two arguments and returns `true` when satisfied and `false` when not satisfied

## Description

Make_heap() function reorders the elements between `fi rst` and `last` in order to create a heap.

The first version compares objects using `operator`< and the second compares objects using a function object `comp`.

None.

## Complexity

The complexity is linear; performs at most `3*(last - first)` comparisons.

### References

Example:
##### Example - make_heap algorithm
Problem
This program illustrates the use of the STL make_heap() algorithm (default version) to convert an arbitrary vector of integers into a heap.
Workings
```#include <iostream>
#include <vector>
#include <algorithm>

using namespace std;

int main()
{
int a[] = {25, 17, 36, 2, 3, 100, 1, 19, 7};
vector<int> v(a, a+9);

cout <<"\nHere are the values in the vector:\n";
for (vector<int>::size_type i=0; i<v.size(); i++)
cout <<v.at(i)<<" ";

cout <<"\nNow we make these values into a (maximum) heap.";
make_heap(v.begin(), v.end());

cout <<"\nHere are the revised contents of the vector:\n";
for (vector<int>::size_type i=0; i<v.size(); i++)
cout <<v.at(i)<<" ";

return 0;
}```
Solution
Output:

Here are the values in the vector:
25 17 36 2 3 100 1 19 7

Now we make these values into a (maximum) heap.

Here are the revised contents of the vector:
100 19 36 17 3 25 1 2 7
References