I have forgotten

• https://me.yahoo.com
COST (GBP)
5.00
0.00
0

# Bracket

Given two initial points, this algorithm finds another point such that a bracketing triple is formed.
Controller: CodeCogs
Contents

C++

## Bracket

 voidbracket( double (*f)(double)[function pointer] double& a double& b double& c )
Given a user-defined function f and two distinct initial points a and b, this algorithm searches in the downhill direction (defined by the function as evaluated at the initial points) and returns a new point c such that the triplet  brackets a minimum of the function. Explicitly, bracketing the minimum means finding three values a, b and c such that


In order to achieve this, an initial guess is made using the golden section


and then parabolic extrapolation is used as described below. Consider


then the new extrapolated abscissa will be


If this does not create a new minimum point , default golden section interval magnification is used


The function takes four parameters.

### Example 1

#include <codecogs/maths/optimization/bracket.h>

#include <iostream>
#include <iomanip>
#include <cmath>

// user-defined function
double f(double x) {
return x * sin(x);
}

int main()
{
double a = 5, b = 4, c;
Maths::Optimization::bracket(f, a, b, c);

std::cout << "The bracketing triple is: " << std::endl << std::endl;
std::cout << "    a = 4" << std::endl << "    b = 5 " << std::endl;
std::cout << "    c = " << std::setprecision(10) << c << std::endl;
std::cout << std::endl;

std::cout << "The corresponding function values are: " << std::endl;
std::cout << std::endl;
std::cout << " f(a) = " << f(4) << std::endl << " f(b) = " << f(5);
std::cout << std::endl;
std::cout << " f(c) = " << f(c) << std::endl << std::endl;
return 0;
}

### Output

The bracketing triple is:

a = 4
b = 5
c = 6.618034

The corresponding function values are:

f(a) = -3.027209981
f(b) = -4.794621373
f(c) = 2.174859828

### Parameters

 f the user-defined function a the left endpoint of the initial interval b the right endpoint of the initial interval c the third point that will complete the bracketing triple

### Returns

The new values of a, b and c creating a bracketing triple.

### Authors

Lucian Bentea (August 2005)
##### Source Code

Source code is available when you buy a Commercial licence.

Not a member, then Register with CodeCogs. Already a Member, then Login.