# Accelerated horizontally

Fluid masses subjected to horizontal acceleration

### Key Facts

**Gyroscopic Couple**: The rate of change of angular momentum () = (In the limit).

- = Moment of Inertia.
- = Angular velocity
- = Angular velocity of precession.

**Blaise Pascal**(1623-1662) was a French mathematician, physicist, inventor, writer and Catholic philosopher.

**Leonhard Euler**(1707-1783) was a pioneering Swiss mathematician and physicist.

**Henry Philibert Gaspard Darcy**(1803-1858) was a French engineer who made several important contributions to hydraulics.

## Overview

Consider a tank, originally at rest and containing some liquid. We know that the liquid, at rest, maintains its surface level as shown in fig-1(a). Now let the tank move towards the right side with a uniform acceleration.##### MISSING IMAGE!

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- = Angle, which the liquid surface makes with the horizontal, and
- = Horizontal acceleration of the tank

##### MISSING IMAGE!

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*A*on the inclined liquid surface as shown in fig-2. We know that the force acting on the liquid particle are : 1. Weight of the particle (W) acting vertically down, 2. Accelerating force (F) acting horizontally towards right, and 3. Pressure (P) exerted by the liquid particles normal to the free surface. We know that the weight of the particle, where, m = Mass of liquid particle, g = Gravitational acceleration Similarly, accelerating force, Now resolving the forces horizontally at

*A*, And resolving the forces vertically at

*A*, Dividing equation (2) by (3) Now consider the equilibrium of the entire mass of the liquid. Let,

- P
_{1}= Hydrostatic pressure on the back side of the tank, and - P
_{2}= Hydrostatic pressure on the front side of the tank

Example:

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##### Example - Fluid masses subjected to horizontal acceleration

Problem

An open rectangular tank 3m long. 2.5m wide and 1.25m deep is completely filled with water. If the tank is moved with an acceleration of 1.5m/s

^{2}, find the slope of the free surface of water and the quantity of water which will spill out of the tank.Workings

Given,

- = 3 m
- = 2.5 m
- = 1.25 m
- = 1.5 m/s
^{2}

**Slope of the free surface of water**Let, = Angle which the free surface of water will make with the horizontal. From equation (#3) we know that,**Quantity of water which will spill out of the tank**From the above figure we can see that the depth of water on the front side, Quantity of water which will spill out of the tank,Solution

Slope =
Quantity of water = litres