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# Velocity and Acceleration of a Piston

An analysis of the velocity and acceleration of a piston.

### Key Facts

**Gyroscopic Couple**: The rate of change of angular momentum () = (In the limit).

- = Moment of Inertia.
- = Angular velocity
- = Angular velocity of precession.

## Introduction

**Key facts**

For a piston with the

**crank**

**radius**, the rod length , the

**crank**

**angle**, and the

**crank**

**angular**

**velocity**, its

**velocity**can be written as: and its

**acceleration**: where .

A reciprocating engine derives its power from the vertical motion of a piston within individual cylinders of the engine. The up-down motion of the piston, also known as reciprocating motion, is converted into rotary motion by use of a crankshaft. Such a mechanism in motion can be seen in

**Figure 2**, where the crankshaft is depicted with red, and the pistons with gray (to see the animation click on the thumbnail). Power transmitted such, requires constant motion of the piston within the cylinder from one extreme to the other. During this motion the velocity of the piston changes constantly; becoming zero at each extreme, and accelerating to a maximum value proportional to the engine RPM (rotations per minute).## Velocity And Acceleration Of A Piston

In order to define the velocity and acceleration of a piston, consider the mechanism in**Figure 1**, where the crank is driven with the uniform angular velocity .

Also, let be the crank radius, the rod length, the position of the piston pin from the crank center, the angle, and the angle (the crank angle). From

**Figure 1**it can be seen that: It can also be noted from

**Figure 1**that: Squaring equation (3) gives: which can also be written as: This eventually leads to: where . By using this expression of in equation (2), we obtain: which can also be written as: and furthermore, as: In order to calculate the piston

**velocity**we differentiate (4) with respect to time, when we get: The piston

**acceleration**can then be calculated by differentiating again with respect to time, when we obtain: Note that in these equations the positive direction of velocity and acceleration is away from the crankshaft. In normal situations and can be neglected in comparison with , and thus, the above equations can be reduced to:

Example:

##### Example - Example 1

Problem

In the crank and slotted lever mechanism diagramed in Figure E1, the crank is driven at a uniform speed of radians per second.

If is the perpendicular from on , being the center-line of the slotted lever, prove that the

Also, find the

If is the perpendicular from on , being the center-line of the slotted lever, prove that the

**angular acceleration**of the slotted lever is given by:Also, find the

**magnitude**and**direction of the acceleration**of the point when the crank angle is , given that , , and . Figure E1Workings

From the diagram we can write that:
From which:
By differentiating (1) with respect to time, we get:
Which leads to:
From Figure E1 we can write that:
Thus, equation (2) becomes:
Or:
By differentiating (2) with respect to time, we obtain:
By substituting in equation (4) with the expression from (3), we can write:
Or:
By replacing the numerical values in equation (1), we can write that:
As:
Equation (6) becomes:
Which gives:
Thus, we get that:
And, by using this value, we also obtain that:
Furthermore, by replacing numerical values in (3) and (5), we respectively get that:
In order to calculate the acceleration of , , we are going to split it in a tangential component, , perpendicular to , and a radial component, , in the direction of (see Figure E1). Also, let be the angle which defines the direction of the acceleration. We can write that:
From which we get the magnitude of acceleration:
Also, as:
We obtain the direction of acceleration:

Solution