Plastic Theory of Bending
Describes Bending above the yield Stress for elastic materials (Mild Steel).
Bending Beyond The Yield Stress.
- Most Engineering design is based on the "Elastic Theory of Bending" and the method is to calculate the maximum Stresses which occur, and to then keep them within the working Stresses in both compression and Tension. These working Stresses are calculated from the Yield (or ultimate) Stress and a Factor of Safety. This approach is a little unrealistic since Mild Steel Structures do not fail when the edge Stress of any cross section reaches the Yield point, and will continue to withstand the load as long as the central core of the section remains within the Elastic State.
Plastic Bending Of Beams
- As the load on a particular beam is gradually increased, the greatest Stresses will occur at the extreme fibres of the "weakest" section (Note : In some Steels when the elastic limit is reached there is a marked reduction in Stress and in any calculations the lower Yield Stress is taken - See graph). These outer fibres are said to be in the plastic state, and any increase in loading will result in a considerable increase in Strain and hence deflection at that section of the Beam. There will also be a redistribution of Stress. With Mild Steel this increase in Strain can take place without the Stress rising above the yield point (i.e. any Strain Hardening effects can be neglected and the plastic Strain at yield is in the order of 10 - 20 times the Elastic Strain). It can therefore be assumed that the Stress in the plastic region is Constant. When the whole cross section at any point in a structure becomes Plastic, no further increase in the moment of resistance is possible without excessive Strain (equivalent to an increase in the Curvature at that section) and a plastic hinge has been developed; one or more such hinges are required for a complete collapse. The number depends upon the type of structure and whether it is, for example, a simply supported beam, a built-in beam or a rigid frame. The value of the load required to produce this state is called the Collapse Load, and the ratio of the Collapse Load to the Working Load is called the Load Factor. In plastic design this factor is used instead of the normal Factor of Safety.
Assumptions In The Plastic Theory.The requirement is to calculate the Bending Moment needed to form a Plastic hinge in any particular cross section, and to determine the distribution of Bending Moment along the beam at the Collapse Load. To do this it is normal to make the following assumptions:-
- That the material exhibits a marked yield and can undergo considerable Strain at Yield without any further increase in Stress. In effect this limits the theory to applications using Mild Steels as the material has a drop in Stress at Yield. The lower yield stress is used in calculations.
- The Yield Stress is the same in Tension and Compression.
- Transverse cross-sections remain plane so that the Strain is proportional to the distance from the Neutral Axis. However, in the Plastic region the Stress will remain Constant and is not proportional to the Strain.
- Once a Plastic Hinge has developed at any cross section, the Moment of Resistance at that point will remain Constant until the collapse of the whole structure has taken effect. This will only happen when the required number of Plastic Hinges at other points have developed.
The Moment Of Resistance At A Plastic Hinge.The diagram shows the variations in Stress and Strain in a beam of symmetrical cross section subjected to a working load.
- (a) Using the formula from the Simple Theory of Bending, the maximum working Stress is . Note that the Stress and Strain are proportional to the distance from the Neutral Axis.
- (b) The load has been increased so that the extreme fibres Yield and the beam is in a partial Plastic state. Note that is the lower Yield Stress.
- (c) The Load is increased further until a fully Plastic State is obtained. It is now assumed that the stress is uniform over the whole cross section. In fact this is not strictly true, since there will be a very small elastic region around the Neutral Axis (shown on the diagram) but the effect of this on the value of the Moment of Resistance is very small and can be neglected.
Moments Of Resistance For Various Cross-sections.a) Rectangular Section If the width is b and the depth d then the Total loads above and below the Neutral Axis are both each acting at from the Neutral Axis. Hence, the Plastic Moment is given by:
Example - Moments Of Resistance For Rectangular Cross-sections
A Steel bar of rectangular cross-section 3 in. by 1.25 in. is used as a simply supported beam over a span of 48 in. with a central load. If the yield Stress is 18 tons/sq.in. and the long edges of the section are vertical, (a) find the load when yielding first occurs. Assuming that a further increase in load causes yielding to spread inwards towards the neutral axis, with the stress in the yielded part remaining at 18 tons/sq.in. , (b) find the load required to cause yielding to a depth of 0.5 in. at the top and bottom of the section at mid span. (c) Find also the length of beam over which yielding has occurred. (U.L.)
If tons is the load at first yield,then from equation (3):
(a) (b) (c) The length of beam over which yielding occurs
Collapse LoadsOnce the Moments of Resistance at a plastic hinge in a section of a beam has been found it is necessary to decide from the conditions at the supports, how many hinges are required to cause Collapse. If there are a number of points of "local" maximum bending moments along the beam (Under working load conditions), it is clear that the first plastic hinge will occur at the numerical maximum point. If further plastic hinges are required for collapse, then these will occur at the next lower value chosen from the remaining local maxima. When sufficient plastic hinges have been formed to convert the structure into a mechanism (i.e. the hinges are considered to be pin joints), then collapse will occur. The case of a single beam supported in three different ways will now be examined. a) A Simply Supported Beam. Let the load divide the length in the ratio of a:b. There is only one point of Maximum Bending Moment (i.e. Wab/l under the load) and the collapse conditions will be reached when a Plastic Hinge is formed at this point, The Bending Moment at the hinge is , and hence the collapse Load is given by:
Example - Application of Collapse Loads
A 12 in. by 4 in. British Standard Beam is carried over a span of 20 ft. and has rigidly built in ends. Find the maximum point load which can be carried at 8 ft. from one end and the maximum working stress which will have been set up.
Combined Bending And Direct StressWhen a Beam or Column is subjected to an axial Stress as well as a Bending Stress, the neutral axis will be displaced to one side of the centroid. (a) in the following diagram shows the variation in working Stress. An increase in load will cause the stress to reach the Yield Point on one side first and then to spread across the section to give a fully plastic state (c). It can be seen that the displacement of the neutral axis in the plastic state is given by h, where:
Example - Application of Combined Bending And Direct Stress
A 12 in. by 5 in. British Standard Beam has to withstand an axial load of 10 tons. If a load factor of 1.8 is to be applied, determine the maximum permissible Bending Moment.
Collapse Loads In Portal FramesIn a framework with rigid joints,under any applied load, points of maximum Bending Moment will occur at the joints. At collapse some or all of the joints will become Plastic Hinges. The diagram shows a portal frame of height h and span l. It is under a central vertical load V and a horizontal load H. Plastic hinges may form in any combination at the points A B C D and E. It should be noted that if A and E are pin jointed, they will rotate under zero Bending Moment. A collapse condition is reached when sufficient hinges are formed to create a "mechanism". The only three forms of collapse mechanism are:-
- Beam Collapse with hinges at B, C and D.
- Sway Collapse with hinges at A, B, D and E
- Combined Collapse with hinges at A,C,D,and E
- for the stanchions AB and DE.
- for the beam BD
- for the corners B and D.
- Vertical Load only. The symmetrical Beam Collapse will apply. A joint rotation of will occur at B and D which equates to at C. If it is assumed that the whole Strain takes place under a constant collapse load and neglecting any elastic strain, then the work done by the Load is , and the energy dissipated in the plastic hinges is . But work done must equal Energy dissipated.
- Horizontal Load only. This will produce a "Sway Collapse with rotations of occurring at B and D. Equating the Work done by the load and at the plastic hinges:
- Combined Load. Generally there will be no rotation at the point B and collapse will be by forming plastic hinges at C and D. The work-Energy equation now becomes:
- Vertical Loading only. The beam collapses in the same way as the hinged- base portal frame. Hence:
- Horizontal Load Only. Sway collapse now requires the formation of 4 hinges and the work equation is:
- Combined Loading. The combined collapse mechanism gives:
Example - Collapse Loads In Hinged Base Portal Frames
If in the above diagram obtain an expression for the horizontal and vertical collapse loads when the Plastic moment is the same for the beam and the stanchions.
From equation (#69)
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